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๐Ÿ“ ์•Œ๊ณ ๋ฆฌ์ฆ˜/Programmers - SQL

[MySQL/PGS] Lv.4 : ๋…„, ์›”, ์„ฑ๋ณ„ ๋ณ„ ์ƒํ’ˆ ๊ตฌ๋งค ํšŒ์› ์ˆ˜ ๊ตฌํ•˜๊ธฐ

by xxilliant 2025. 6. 9.
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https://school.programmers.co.kr/learn/courses/30/lessons/131532

 

ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค

SW๊ฐœ๋ฐœ์ž๋ฅผ ์œ„ํ•œ ํ‰๊ฐ€, ๊ต์œก์˜ Total Solution์„ ์ œ๊ณตํ•˜๋Š” ๊ฐœ๋ฐœ์ž ์„ฑ์žฅ์„ ์œ„ํ•œ ๋ฒ ์ด์Šค์บ ํ”„

programmers.co.kr


ํ”„๋กœ๊ทธ๋ž˜๋จธ์Šค ๋ ˆ๋ฒจ 4

mysql group by ๋ฌธ์ œ์ด๋‹ค.

๊ตฌ๋งคํ•œ ์œ ์ € ์ˆ˜๋ฅผ ์นด์šดํŒ…ํ•˜๋ฏ€๋กœ distinct๋ฅผ ๊ผญ ์‚ฌ์šฉํ•ด์ค˜์•ผ ํ•œ๋‹ค!!!!

 

๋‚˜์˜ ํ’€์ด

select year(SALES_DATE) as YEAR, month(SALES_DATE) as MONTH, GENDER, count(distinct(a.USER_ID)) as USERS
from USER_INFO a, ONLINE_SALE b
where a.USER_ID = b.USER_ID and a.GENDER is not null
group by YEAR, MONTH, GENDER
order by YEAR, MONTH, GENDER;

 

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